Fibonacci's
Rabbits
- Flowy - XB -
The original problem that Fibonacci investigated (in the year
1202) was about how fast rabbits could breed in ideal circumstances.
How many pairs will there be in one year?
1.
At the end of the first month, they mate, but there is still one
only 1 pair.
2.
At the end of the second month the female produces a new pair, so
now there are 2 pairs of rabbits in the field.
3.
At the end of the third month, the original female produces a
second pair, making 3 pairs in all in the field.
4.
At the end of the fourth month, the original female has produced
yet another new pair, the female born two months ago produces her first pair
also, making 5 pairs.
The number of pairs of rabbits in the field at the start of each month is 1, 1,
2, 3, 5, 8, 13, 21, 34, ...
Now can you see why this is the answer to our Rabbits problem?
The diagram above represent the same information. Rabbits have been numbered to enable comparisons and to count them, as follows: |
·
All the rabbits born in the same month are of the same generation
and are on the same level in the tree.
·
The rabbits have been uniquely numbered so that in the same
generation the new rabbits are numbered in the order of their parent's number.
Thus 5, 6 and 7 are the children of 0, 1 and 2 respectively.
·
The rabbits labelled with a Fibonacci number are the children of
the original rabbit (0) at the top of the tree.
·
There are a Fibonacci number of new rabbits in each generation,
marked with a dot.
·
There are a Fibonacci number of rabbits in total from the top down
to any single generation.
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